A satellite is orbitting around the earth wit | vedclass

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Question

$v_{a}=\frac{d A}{d t}=\frac{1}{2} r v \Rightarrow v_{a}^{2}=\frac{1}{4} r^{2} v^{2}$

$\Rightarrow v_{a}^{2}=\frac{1}{4} r^{2} 	imes \frac{g R^{2}

Vedclass · Accepted Answer

$\frac{{4v_a^2}}{{g{R^2}}} - R$

Vedclass · Answer

$v_{a}=\frac{d A}{d t}=\frac{1}{2} r v \Rightarrow v_{a}^{2}=\frac{1}{4} r^{2} v^{2}$

$\Rightarrow v_{a}^{2}=\frac{1}{4} r^{2} 	imes \frac{g R^{2}}{r}$

$\mathrm{r}=\frac{4 \mathrm{v}_{\mathrm{a}}^{2}}{\mathrm{g} \mathrm{R}^{2}} \quad 	herefore \mathrm{h}=\frac{4 \mathrm{v}_{\mathrm{a}}^{2}}{\mathrm{g} \mathrm{R}^{2}}-\mathrm{R}$

A satellite is orbitting around the earth with areal speed $v_a$. At what height from the surface of the earth, it is rotating, if the radius of earth is $R$

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